@jeanpo Can you do
uid <- "xxxxxxxxxxxxxxxxxx"
form <- kobo_form(uid)
form |>
filter(name == "var_name") |>
pull(choices)
when I do it with my example, I have:
filter(form, name == "pet_type") |> pull(choices)
## # A tibble: 5 × 4
## value_name value_label value_lang value_version
## <chr> <chr> <chr> <chr>
## 1 1 lapin English (en) vTbjhgntR6d4h6ZvWahofi
## 2 2 poulet English (en) vTbjhgntR6d4h6ZvWahofi
## 3 3 chien English (en) vTbjhgntR6d4h6ZvWahofi
## 4 4 chat English (en) vTbjhgntR6d4h6ZvWahofi
## 5 5 tortue English (en) vTbjhgntR6d4h6ZvWahofi
Can you also do this:
kobo_asset_version_list(uid)
## # A tibble: 4 × 4
## uid url asset_deployed date_modified
## <chr> <chr> <lgl> <dttm>
## 1 vTbjhgntR6d4h6ZvWahofi http… TRUE 2023-05-19 15:40:40
## 2 vKdkehR7oT9psemeiE85ve http… TRUE 2023-05-19 15:39:28
## 3 vSmBN6KCy6rV6KbeGuH8g7 http… FALSE 2023-05-19 15:38:49
## 4 vQJkKVJLiPLQAFz2nbDXFQ http… FALSE 2023-05-19 15:38:48
Finally, what’s the output of this?
df <- kobo_data(uid)
df[["__version__"]]
table(df[["__version__"]])