Advanced skip logic set up

Can you all please help me to set the logic for the below scenario?

  1. How many people with disability are in your household?
    The answer can be: 1…………2…………3

  2. What types of people with disability are there?
    The answer can be: Seeing disability…. Hearing disability……Walking disability…… Remembering disability

In this scenario, I want to see, if the answer of the 1st question is 2, then 2nd question will appear 2 times for two children and , if the answer of the 1st question is 3, then 2nd question will appear 3 times for three children. What will be skip logic here?
Or Provide a list or source where all difficult logics are available. Thank you so much.

Hi @arfathabib and welcome back to the community!

You can use repeat groups for your request, and you can use how many iterations of the repeat groups, you can learn more about it in the help article:

https://support.kobotoolbox.org/group_repeat.html#controlling-the-loop-of-repetition-in-a-roster

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@hakan_cetinkaya, :clap: :heart: :partying_face:

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Thank you so much for your tremendous support.

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